16s^2-14s+3=0

Solution for 16s^2-14s+3=0 equation:

16s^2-14s+3=0

a = 16; b = -14; c = +3;
Δ = b2-4ac
Δ = -142-4·16·3
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2}{2*16}=\frac{12}{32}
=3/8
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2}{2*16}=\frac{16}{32}
=1/2
$